Sets - Test Papers
CBSE Test Paper 01
CH-01 Sets
- Section A
Let U be the universal containing 700 elements. If A and B are subsets of U such that n(A) = 200, n(B) = 300 and then
400
300
500
800
If A = { 1,2,3,4 } , B = { 4,5,6,7 } ,
{ 4 }
{ 1,2,3,4 }
{ 6 , 7 }.
{ 1, 2 }
If n (A ) =3 and n ( B ) = 6 and A B , then
9
3
6
none of these
The number of proper subsets of the set { 1, 2 , 3 } is :
6
7
8
5
If A class has 175 students . The following data shows the number of students offering one or more subjects. Mathematics 100 ; Physics 70 ; Chemistry 40 ; Mathematics and Physics 30 ; Mathematics and Chemistry 28 ; Physics and Chemistry 23 ; Mathematics , Physics and Chemistry 18 . How many students have offered Mathematics alone?
35
22.
48
60
- Fill in the blanks:
If A = {1, 3, 5, 7, 9} and B = {2, 3, 5, 7, 11}, then AB is ________.
- Fill in the blanks:
A set, consisting of a single element, is called a ________.
List all the elements of set {x : x is a month of a year not having 31 days}.
State whether the statement is true or false: {a, e, i, o, u) and {a, b, c, d} are disjoint sets.
If U = {a, b, c, d, e, f, g, h}, find the complement of the set: D = {f, g, h, a}
Let A = {1, 2, 4, 5} B = {2, 3, 5, 6} C = {4, 5, 6, 7}. Verify:
If A is any set, prove that:
In a survey of 60 people, it was found that 25 people read newspaper H, 26 read newspaper T, 26 read newspaper I, 9 read both H and I, 11 read both H and T, 8 read both T and I, 3 read all three newspapers.
Find: the number of people who read at least one of the newspaper.For any two sets A and B prove that:
If U = {a, b, c, d, e, f} , A = {a, b,c}, B = {c, d, e, f} , C = {c, d, e} and D = {d, e, f}, then tabulate the following sets:
- A D
- A C
- U D
- ()'
- (U A)'
CBSE Test Paper 01
CH-01 Sets
Solution
Section A
- (b) 300
Explanation:
Given n(A) = 200, n(B) =\ 300,= 200 + 300 - 100 = 400
= 700 - 400 = 300
[By De morgans law] - (a) { 4 }
Explanation: Given A=1,2,3,4 and B=4,5,6,7 - (c) 6
Explanation: - (b) 7
Explanation: The no of proper subsets=2n-1=23-1=7
Here n=no of elements of given set=3 - (d) 60
Explanation:
M -mathematics
P - physics
C - chemistry
Venn Diagram
By Venn Diagram we can see that the students who offered mathematics alone are 60. {1, 2, 9, 11}
singleton set
A month has either 28, 29, 30 or 31 days.
Out of the 12 months in a year, the months that have 31 days are:
January, March, May, July, August, October, December
Given set has elements {February, April, June, September, November}Let A = {a, e, i, o, u} and B ={a, b, c, d}
Now = {a}
Hence A and B are not disjoint. So the statement is false.={b, c, d, e}
A = {1,2,4,5}, B = {2,3,5,6}, C = {4,5,6,7}
= {2,3,4,5,6,7}
= {1} .....(i)
(A - B) = { 1, 4}
(A - C) = {1, 2}
= {1} .......(ii)
From eqn (i) and eqn (ii), we getThe symbol '' stands for if and only if (in short if).
In order to show that two sets A and B are equal, we show that and
We have is a subset of every set,
Hence A =
To show the backward implication, suppose that
every set is a subset of itself
Hence, proved.Here
n(U) = a + b + c + d + e + f + g + h = 60 ....... (i)
n (H) = a + b + c +d = 25 ....... (ii)
n(T) = b + c + f + g = 26 ........ (iii)
n(I) = c + d + e + f = 26 ....... (iv)
....... (v)
....... (vi)
....... (vii)
....... (viii)
Putting value of c in (vii),
3+ f = 8 f = 5
Putting value of c in (vi),
3 +b = 11 b = 8
Putting values of c in (v),
3 + d = 9 d = 6
Putting value of c, d, f in (iv),
3 + 6 + e + 5 = 26 e = 26 - 14 = 12
Putting value of b, c, f in (iii),
8 + 3 + 5 + g = 26 g = 26 - 16 = 10
Putting value of b, c, d in (ii)
a + 8 + 3 + 6 = 25 a = 25 - 17 = 8
Number of people who read at least one of the three newspapers
= a + b + c + d +e + f + g
= 8 + 8 + 3 + 6 + 12 + 5 + 10 = 52Let
and
and
. . . (i)
Let
and
and
. . . . (ii)
From (i) and (ii), we haveAccording to the question, we are given that,
U = {a, b, c, d, e, f} , A = {a, b,c}, B = {c, d, e, f} , C = {c, d, e} and D = {d, e, f}- A D = {a, b,c} {d, e, f} =
- A C = {a, b, c} {c, d, e} = {c}
- U D = {a, b, c, d, e, f} {d, e, f} = {d, e, f}
- = {a, b, c} {} = {a,b,c}
- U = {a, b, c, d, e, f} {} =
()'
=
= U - U A = {a, b, c, d, e, f} {a, ,b, c}
= {a, b, c, d, e, f}
= U
(U A)' =